Hi,
Solving this puzzle I arrive to the picture here https://zupimages.net/up/23/44/4in7.png. I don't find a more elegant way than see 1 or 5 R3C9 implies same digit R4C7 and then R8C8 as 1 and 5 are already R9 C 2 and 4. So I can place 8 R9C8. Do you solve it differently ?
Sincerely.
I answer myself. We can see 1
I answer myself. We can see 1 and 5 lie in R4C8 and R3C9 so neither can be in R1C8. It implies 4 R1C8 and 8 R9C8. I probably just needed to write it.
Thank you.