Permalink Submitted by Mike on Mon, 07/27/2026 - 17:24.
The first steps are: R1C3=2, R5C5=7, R1C7=4, R4C5=R1C6=5, R8C7=R4C9=R6C1=8, R4C3=R6C7=R2C9=R8C1=6, R8C3=9 (naked single).
Now let's look at the digits 6, 8 and 9 in Box 8. Their possible positions are all at most R7C4, R7C5 and R7C6, so these three cells must contain these three digits. Therefore, other digits cannot be in these cells. It follows that R9C4=2 and R9C5=4.
Permalink Submitted by calacala on Mon, 08/03/2026 - 20:00.
Thank you for your reply. I found a way to solve it without test. I didn't think there was an easier way and could possibly be rated a litlle more. I'm not sure we talk about the same grid as it's not possible to put a 2 R1C3. Sorry also for the possible mistake. I remembered the grid was 28 points, so it should be the 4th of GP 6.
Permalink Submitted by Mike on Tue, 08/04/2026 - 12:18.
In the 4th Classic Sudoku of GP6, there is a hidden triplet of 2, 3 and 4 in Box 2.
Another coincidence is that the 4th Classic Sudoku of GP6 and GP7 are both 28 points.
Hidden Triplet
The first steps are: R1C3=2, R5C5=7, R1C7=4, R4C5=R1C6=5, R8C7=R4C9=R6C1=8, R4C3=R6C7=R2C9=R8C1=6, R8C3=9 (naked single).
Now let's look at the digits 6, 8 and 9 in Box 8. Their possible positions are all at most R7C4, R7C5 and R7C6, so these three cells must contain these three digits. Therefore, other digits cannot be in these cells. It follows that R9C4=2 and R9C5=4.
Thank you for your reply. I
Thank you for your reply. I found a way to solve it without test. I didn't think there was an easier way and could possibly be rated a litlle more. I'm not sure we talk about the same grid as it's not possible to put a 2 R1C3. Sorry also for the possible mistake. I remembered the grid was 28 points, so it should be the 4th of GP 6.
Hidden Triplet too
In the 4th Classic Sudoku of GP6, there is a hidden triplet of 2, 3 and 4 in Box 2.
Another coincidence is that the 4th Classic Sudoku of GP6 and GP7 are both 28 points.